So far, we have set up Punnett squares to solve monohybrid crosses, where one trait was involved. Dihybrid crosses are crosses where two different...

So far, we have set up Punnett squares to solve monohybrid crosses, where one trait was involved. Dihybrid crosses are crosses where two different traits (pairs of alleles) are involved.There is a mutant C. elegans that rolls around on the plates. This mutation is called roller (rol-2) and is denoted by r. It is recessive to wild-type (R). There is another mutant C. elegans that is short and fat. This mutation is called dumpy (dpy- 5) and is denoted by d. It is recessive to wild-type (D). You want to create a worm that is both dumpy and a roller. The problem is that male rollers and hermaphrodite dumpies cannot mate because the males cannot catch up with the hermaphrodites. However, you can cross a hermaphrodite roller to a wild-type male and a hermaphrodite dumpy to a wild-type male to make heterozygous offspring.What are the genotypes and phenotypes of the F1 progeny for the following cross? Cross 1Parents: ddRR hermaphrodite X DDRR maleA. Genotypes: 1:2:1 DDRR: DdRR: ddRR; Phenotypes: 3:1 wild-type: dumpy non-roller