Suppose five cards are drawn from a standard 52 card deck of playing cards with all possibilities being equally likely.

Suppose five cards are drawn from a standard 52 card deck of playing cards with all possibilities being equally likely.

TWO PAIR is the events that two cards both have one number, two other cards both have some other number, and the fifth card has a number different fro the other two number. What is P(TWO PAIR)?

This is how I address the question:

P = {13*12*11*4!/(2!*2!)*4!/(2!*2!)*4!/3!} / {52!/(5!*48!)} but I did wrong.