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suppose that f(x) and g(x) are diferrentiable functions such that f(6)=1, f' (6)=9, g(6)=8 and g'(6)=3.
suppose that f(x) and g(x) are diferrentiable functions such that f(6)=1, f' (6)=9, g(6)=8 and g'(6)=3. Find h'(6) when h(x)=f(x)/g(x)
h'(6)=
f(6)=1, f' (6)=9, g(6)=8 and g'(6)=3. h' ( 6 )= f ' ( 6 )∗g ( 6 )−g' ( 6 )∗f ( 6 ) 9∗8−3∗1 72−3 69===2646482( g ( x ))