The compound PtCl2 (NH3)2 is effective as a treatment for some cancers. It is synthesized by the reaction shown in the following equation. K2 PtCl4(aq) + 2NH3 (aq) ⟶ 2KCl (aq) + PtCl2 (NH3)2(aq). Ho

The compound PtCl2 (NH3)2 is effective as a treatment for some cancers. It is synthesized by the reaction shown in the following equation. K2 PtCl4(aq) + 2NH3 (aq) ⟶ 2KCl (aq) + PtCl2 (NH3)2(aq). How many moles of K2 PtCl4 must react in order to produce 30.0 g PtCl2 (NH3)2?

A) 0.100 mol K2 PtCl4

B) 0.200 mol K2 PtCl4

C) 0.140 mol K2 PtCl4

D) 0.160 mol K2 PtCl4