The distance s (in m) above the ground for a projectile fired vertically upward with a velocity of 4[a]m/s as a function of time t (in s ) is given...

The distance s (in m) above the ground for a projectile fired vertically upward with a velocity of 4[a]  m/s as a function of time t (in s ) is given by s=4[a]t−4.[b]t^2..

a=3, b=7

find t for v=0 , find v for t=4, find v for t=5. What conclusions can you draw?

Example if your values are a=3 and b=5 then formula you work with would be s=43t - 4.7t^2