The gravitational force between two point masses x meters apart is given by, f(x)= (23*10^-29)/x^2 (a) Suppose one mass is held fixed at the point

The gravitational force between two point masses x meters apart is given by,f(x)= (23*10^-29)/x^2(a) Suppose one mass is held fixed at the point (1,0) on the x-axis (units in meters). How much work is required to move a second mass along the x-axis from the point (-1,0) to the origin?(b) Suppose two masses are fixed at (1,0) and (-1,0). Setup but do not solve an integral for the work required to move a third mass along the y-axis from (0,1) to the origin.