the position of a 2kg object as a function of time is given by the following expression:

the position of a 2kg object as a function of time is given by the following expression: x(t)=2+4t+3t^2 where x is in meters and t is in secondsfor the time interval 0 to 10, draw the object's postion,velocity and acceleration vs time on the graph, calculate the net force acting on the object in time interval between 0 and 10.is it a constant force