The solubility product constant for K2PdCl6 is 6.010-6 K2PdCl6 (s) -- 2 K+ (aq) + PdCl6 2- (aq) What is the K concentration of a solution prepared...

The solubility product constant for K2PdCl6 is 6.0×10–6

K2PdCl6 (s) <--> 2 K+ (aq) + PdCl6 2- (aq)

What is the K concentration of a solution prepared by mixing 50.0 mL of 0.400 M KCl with 50.0 mL of

a) 0.100 M PdCl62– 

= ? M

b) 0.200 M PdCl62– ?

= ? M

c) 0.400 M PdCl62– ?

= ? M

(a question almost the same as been solved previously on here, but the ksp and last molar value is different and even when I follow along and insert my numbers, I'm not getting the right answers)