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What is pH of the solution? 120 mg Na2HPO4 and 100 mg of NaH2PO4 dissolved in 1 L of deionized water.
Using the Henderson-Hasselbach equation, =7.21
pH= pKa+log##([HPO_4^-2]/[H_2PO_4^-1])## pH=7.20+log##((8.453*10^-4)/(8.347*10^-4))## pH=7.21