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# What is the decay equation for the beta decay of uranium 237?

The for the of **Uranium-237** looks like this:

##""_92^237U -> ""_93^237Np + beta + bar nu##

##beta## represents an electron, also called a **beta-particle**, and ##barnu## is an antineutrino. Let's verify that the equation is in accordance with the definition of a .

During a , a neutron from the nucleus of **U-237** emits an electron, which is a negatively-charged particle. Since the neutron can be considered to be a combination of a beta-particle and a proton, the emission of an electron will leave behind one proton.

This will cause the to increase by **1**, but leave the unchanged. Indeed, the beta decay of **U-237** leads to the formation of **Neptunium-237**, which has the same , 237, but a different , 93.