What is the electron configuration for an oxygen atom in an excited state? thank you :)

The ground state for an oxygen atom is ##"1s"^2"2s"^2"2p"^4"##. In an excited state, a 2p electron could absorb energy and jump to a 3s orbital. The electron configuration for the oxygen atom in its excited state would then be ##"1s"^2"2s"^2"2p"^3"3s"^1.## This is not a stable electron configuration, and the excited electron would immediately drop back to the ground state configuration, releasing a photon of energy equal to the amount of energy originally absorbed by the electron.