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QUESTION

# What is the oxidation number of each element in kclo3?

"K" -> +1 "O" -> -2 "Cl" -> +5

Wasn't sure which element you were referring to but for a start, "K" and "O" oxidation states are fixed by rules and .

"Cl" has variable oxidation states, and can be determined algebraically :

If x is oxidation number for "Cl", and since no charge overall for the compound, then

(+1) + x + 3 xx (-2) = 0

x - 5 = 0 implies x=+5