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What is the pH at the equivalence point when 30.0mL of 0.175 mol/L HCOOH is titrated with 0.135 mol/L NaOH?

What is the pH at the equivalence point when 30.0mL of 0.175 mol/L HCOOH is titrated with 0.135 mol/L NaOH? Assume the temperature is 25 degrees celcius. For HCOOH, pKa=3.74 at 25 degrees celcius.

Solution to 8124087Reaction: HCOOH + NaOH H2O + HCOONa Mol of HCOOH = 0.175 M/L x 0.03 L = 0.00525 MMol of HCOOH used = Mol of NaOH used= Mol of HCOONa formedVol. of NaOH = 0.00525/ 0.135 =...
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