What is the square root of 6 in simplest radical form?

The square root pf a number can be simplified only if the number is divisible by a perfect square (other than 1).

##sqrt12## can be simplified because ##12## is divisible by ##4## -- a perfect square. ##sqrt12 = sqrt(4xx3) = sqrt4xxsqrt3=2sqrt3##

##sqrt250## can be simplified because ##250## is divisible by ##25## ##sqrt250 = sqrt(25xx10)=sqrt25xxsqrt10=5sqrt10##

But ##6## is not divisible by a perfect square, so ##sqrt6## cannt be simpified further.