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QUESTION

What's ##42 2/3## divided by ##1/3##?

##42 2/3 -: 1/3=128##

##color(blue)("For a moment consider just the "42 2/3)##

write this as ##42+2/3##

This is the same as:

##" "[42color(magenta)(xx1)]+2/3##

But we can write 1 as ##3/3## giving:

##" "[42color(magenta)(xx3/3)]+2/3##

##" "[126/3]" "+2/3 = 128/3##

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ##color(blue)("Putting it all together")##

##42 2/3 -: 1/3" "=" "128/3-:1/3##

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ##color(blue)("Shortcut method")## Turn the ##1/3## upside down and multiply

##128/3xx3/1 " "=" "3/3xx128/1 " "=" "1xx128" "=" "128##

Or by cancelation (which is the same thing really):

##128/(cancel(3))xx(cancel(3))/1 = 128/1=128##

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