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Why are there no solutions to the problems? Trying to get help solving the following quesiton...9.One mole of water at the initial conditions of 0.0◦C and 1atm of pressure is turned to steam (final conditions 100C and 1atm of pressure) by the following two paths. Do you expect ∆S for each path will be the same or different and why? Calculate ∆S for each step along each path assuming the heat capacity for water and steam is constant, 75.48J/K mol and 35.54 J/K mol respectively. Calculate the total ∆S for each path.a.Path a i.the water is heated at constant P =1 atm to 100◦Cii.allowed to boil to steam (∆vapH◦=40.67 kJ/mol at this temperature)b.Path bi.The pressure is lowered to 0.006 atm (to calculate ∆S for this step this you need the value for α which is 0.000214/K for water)ii.the water evaporates to steam at 0.0◦C (∆vapH◦=44.92 kJ/mol at this temperature)iii.The steam is heated to 100◦C at a constant pressure of 0.006atmiv.The steam is compressed to 1atm at constant temperature of 100◦C
