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x=317 n=350 Success rate(p) = x/n = 0.9057 = 0.1 Z/2 = 1.282 Null Hypothesis = Ho: p = 0.90 Alternative Hypothesis = H1 : p 0.90 z = p - p /(square...
x=317
n=350
Success rate(p) = x/n = 0.9057
α= 0.1
Zα/2 = 1.282
Null Hypothesis = Ho: p = 0.90
Alternative Hypothesis = H1 : p > 0.90
z = p̂ - p /(square root (p (1-p))/n)
= (317/350) - 0.90/ square root((0.90)(1-0.90))/350
= 0.0057142857 / 0.0160356727
=0.3563471553 = 0.3563
Zo = 0.3563
Critical Value
Zα/2 = 1.282
|zo | < | z alpha |
p-value: right tail - Ha : ( p > 0.35635 ) = 0.36079
p̂= x/n 317/350 = 0.9057142857
Ho : 0.3563
H1: 0.36079
There are 317 (2s) and 33 (1s)
QUESTION :
Based on your sample proportion, what is the probability of randomly choosing 3 of the 350 participants and finding all 3 that would not purchase another lexus ?(calculations)
