you mix 6.0 mL of .50 M Cu(NO3)2 with 1.0 mL of .50 m KI and collect and dry the CuI precipitate. Calculate the following: moles of Cu(NO3)2 used:...

you mix 6.0 mL of .50 M Cu(NO3)2 with 1.0 mL of .50 m KI and collect and dry the CuI precipitate. Calculate the following:moles of Cu(NO3)2 used:moles of KI used:moles of CuI precipitate expected from KI:What mass of CuI do you expect to obtain from this reaction?If the mass of the precipitate you recover is .038g, what is the percent recovery of the precipitate?

you mix 6.0 mL of .50 M Cu(NO3)2 with 1.0 mL of .50 m KI and collect and dry the CuI precipitate. Calculate thefollowing:moles of Cu(NO3)2 used: 0.00025 moles of KI used: 0.0005moles of CuI...