A coin is flipped 12 times. What is the probability of getting exactly 8 heads?

##495/4096##

The number of possible sequences of heads and tails in ##12## coin tosses is:

##2^12 = 4096##

The number of ways that such a sequence could contain exactly ##8## heads is the number of ways of choosing ##8## out of ##12##...

##((12),(8)) = (12!)/((8!)(4!)) = (12xx11xx10xx9)/(4xx3xx2xx1) = 495##

So the probability of exactly ##8## heads in ##12## coin tosses is:

##495/4096##