A mass of 4.00 g of H2(g) reacts with 2.00 g of O2(g). If 1.94 g of H2O(l) is collected, what is the percent yield of the reaction?

A mass of 4.00 g of H2(g) reacts with 2.00 g of O2(g). If 1.94 g of H2O(l) is collected, what

is the percent yield of the reaction?

2H2(g) + O2(g) → 2H2O(l)

Can someone please show the steps how they got this and preferably with dimensional analysis? Thanks