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# f(x) = x 2 +lnx. What is f'(5)?

f(x) = x2+lnx. What is f'(5)?

Please help. I'm very confused.

Given function isf (x) = x2 + ln x.Thenf 0 (x) When x = 5f 0 (5) = [2 × 5] + d(f (x))dxd 2=(x + ln x)dxdd 2(x ) +(ln x)=dxdx1= 2x2−1 +x1= 2x + .x= 1150 + 151= 10 + =...