How do I graph the quadratic equation ##y=(x-4)^2-6##?

This is a parabola in the form of ##y = (x - h)^2 + k## where ##(h, k)## is the parabola's vertex.

For this particular equation, the vertex is at ##(4, -6)##

The sign of ##x^2## is positive so we have a parabola opening upward.

As a quadratic equation though, substitute specific values for X (or Y) and compute for the value of Y (or X) to get specific points of the graph.