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QUESTION

# How do I graph the quadratic equation y=(x-4)^2-6?

This is a parabola in the form of y = (x - h)^2 + k where (h, k) is the parabola's vertex.

For this particular equation, the vertex is at (4, -6)

The sign of x^2 is positive so we have a parabola opening upward.

As a quadratic equation though, substitute specific values for X (or Y) and compute for the value of Y (or X) to get specific points of the graph.