How do you graph ## ln(x-2)##?

I'll simplify the equation, so it is easier to read.

##y=1ln(1x-2)+0## There is not shifting or movement of anykind except for the ##x-2##, so the ##ln## graph will be moved 2 units right.

So it's just the usual ##ln## graph with 2 units moved right.

Here is a graph for reference. graph{ln(x-2) [-4.75, 15.25, -4.68, 5.32]}