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QUESTION

# How would you balance Ag2O --&gt; Ag + O2?

2Ag_2O-> 4Ag + O_2

How to balance? We have an equation; Ag_2O -> Ag + O_2 First of all balance the O on both sides, now look at the product side. We have 2 oxygen on right side and on left side we have only 1 oxygen. To balance it, put a coefficient 2 on left side before Ag_2O . The equation becomes as 2Ag_2O -> Ag + O_2 Now again check the product side, There is 1 Ag but in reactant side there is 4 Ag. Now put coefficient 4 before Ag on right side. The equation becomes as; 2Ag_2O-> 4Ag + O_2