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QUESTION
How would you balance Ag2O --> Ag + O2?
##2Ag_2O-> 4Ag + O_2##
How to balance? We have an equation; ##Ag_2O -> Ag + O_2## First of all balance the O on both sides, now look at the product side. We have 2 oxygen on right side and on left side we have only 1 oxygen. To balance it, put a coefficient 2 on left side before ##Ag_2O## . The equation becomes as ##2Ag_2O -> Ag + O_2## Now again check the product side, There is 1 Ag but in reactant side there is 4 Ag. Now put coefficient 4 before Ag on right side. The equation becomes as; ##2Ag_2O-> 4Ag + O_2##
