Imagine you have a saturated solution of ca(oh)2, at equilibrium, that has some undissolved ca(oh)2 solid on the bottom of the test tube. if you add an additional scoop of solid ca(oh)2 to this soluti

Imagine you have a saturated solution of ca(oh)2, at equilibrium, that has some undissolved ca(oh)2 solid on the bottom of the test tube. if you add an additional scoop of solid ca(oh)2 to this solution will the concentration of [oh-] in the solution increase, decrease, of be unchanged? (briefly explain and assume we let the solution reach equilibrium again) ca(oh)2(s) <--> ca2+(aq) + 2oh-(aq)