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QUESTION
Using tables, fi nd the inverse Laplace transform of F(s)= (s/(s^2-6s+10))*e^-3s
Using tables, find the inverse Laplace transform ofF(s)= (s/(s^2-6s+10))*e^-3s
solution Step1 make perfect square of s26s+10 S26s+10 = (s3)2+1Step2 find L1 [s/(s2 6s+10) ]L1 [s/{(s3)2 +1}= L1 [{(s3)+3}/{(s3)2 +1}]=L1 [(s3)/{(s3)2 +1} +...