Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.
QUESTION
What is the average deviation of ##1.76, 2.28, 1.90##?
mean deviation ##=0.2##
Compute mean ##barx##
##barx=(1.76+2.28+1.90)/3=1.98##
Mean deviation ##=(sum abs(x-barx))/n##
Mean deviation ##=(abs(1.76-1.98)+abs(2.28-1.98)+abs(1.90-1.98))/3##
Mean deviation ##=0.2##
God bless....I hope the explanation is useful.
