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QUESTION

How do I find the directrix of the parabola y=2x^2?

To find the directrix of a parabola wohse equation is y=ax^2+bx+c you can use this formula: y= (-1-(b^2-4ac))/(4a) So in case of this parbola y=2x^2 the directrix is y=(-1-(0^2-4*2*0))/(4*2) y=-(1)/(8)